TRIGONOMETRIC EQUATIONS Solving Inequalities (Page 3 of 6)

For an optimal window, we consider the period and amplitude. The period will be 2π(365/2π) = 365. The amplitude is 1, but the graph has been shifted upward 1/2 unit, so the range will be (-1/2, 3/2). We will set the WINDOW to accommodate the period and the range (we added a bit of extra space on the range). Also, we have set the scale on the x-axis to 31 to represent about a month in time (assuming the period of 365 correlates to one year).

 WINDOW key....

 GRAPH key.

 Calculator screen image. Calculator screen image.
Copyright © 2010 Turner Educational Publishing
Go back to the previous page. Go to the next page. Go to the Table of Contents. Go to the Index page. Go to the Quiz page. Exit to the Home page.